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Unformatted text preview: | 2 + 3i | of 2 + 3i is the square root of 2 + 3i times its complex conjugate 2 3i: | 2 + 3i | = r (2 + 3i)(2 3i) = r 2 2 (3i) 2 . Since i 2 = 1, | 2 + 3i | = 13. 2.1.5 Solution mathcplx-e Question: Verify that (2 3i) 2 is still the complex conjugate of (2+3i) 2 if both are multiplied out. Answer: (2 3i) 2 = 5 12i and (2 + 3i) 2 = 5 + 12i. 2.1.6 Solution mathcplx-f Question: Verify that e 2i is still the complex conjugate of e 2i after both are rewritten using the Euler formula. Answer: e 2i = cos(2) i sin(2) and e 2i = cos(2) + i sin(2). 2.1.7 Solution mathcplx-g Question: Verify that p e i + e i P / 2 = cos . Answer: Apply the Euler formula for both exponentials and note that sin( ) = sin ....
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This note was uploaded on 11/13/2011 for the course PHY 4458 taught by Professor Garvin during the Fall '11 term at University of Florida.
- Fall '11
- Special Relativity