Linear Prog COP4355_Part_46

Linear Prog COP4355_Part_46 - 188 15.19 Chapter 15 Decision...

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188 Chapter 15 Decision Analysis 15.19 Maximax – Manufactue; Maximin – Buy; Hurwicz ( α = 0.3) – Buy; LaPlace – Buy; Savage – Buy. EV – 50, Buy. 15.20 EVII - .450008. Efficiency - .1500003. 15.21 EV(A l |Good) = 802.0834; EV(A 2 |Fair) = 533.333; EV(A 2 |Poor) = 29.03226). EVII = 18, Efficiency = .45.
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Solutions Manual and Workbook 189 Chapter 16 Waiting Lines (Queues) 16.1 A = 10/hr., S = 1 MST = 11/hr., U = A S = 10 = .91 11 , s 11 T = = x 60 = 60 minutes S - A 11 - 10 Q = s T UT = .91 x 60 = 54.6 minutes S s 1 N = AT = x 60 = 10 customers 6    Yes 16.2 A = 1 2 x 60 = 30/hr., S = 1 x 60 = 40/hr 3 2 , U = A S = 30 40 = .75 () s = x 60 = 6 minutes S - A 40 - 30    Q = s T UT = .75 x 6 = 4.5 minutes S s 1 N = AT = x 6 = 3 customers 2 Yes 16.3 1 A = x 60 = 12/hr. 5 , S 1 = x 60 = 15/hr 4 (a) 22 Q A 12 144 N = = = = 3.2 S S - A 15 15 - 12 45 (b) S = = 20 min S - A 3 (c) 0 A1 2 P = 1 - U = 1 - = 1 - = .2 S1 5
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190 Chapter 16 Waiting Lines (Queues) 16.3 (continued) (d) 1 – (P 0 + P 1 + P 2 ) = P(N > 2) P 0 = .2 P 1 = (1 - .8)(.8) 1 = .16 P 2 = (1 - .8)(.8) 2 = .128 P n>2 = 1 – (.2 + .16 + .128) = 1 - .488 = .512 16.4 (a) 60 = 7.5 mins. 8 (b) 60 = 6.0 mins. 10 (c) 8 arrivals/hr. (d) 10 customers/hr. (e) S 11 T = = = .5 = 30 min S - A 10 - 8 (f) () Q A8 8 = = = .4 = 24 mins. S S - A 10 10 - 8 20 (g) 6 mins (h) S N = = = 4 customers S - A
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This note was uploaded on 11/13/2011 for the course COP 4355 taught by Professor Koslov during the Spring '10 term at University of Florida.

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Linear Prog COP4355_Part_46 - 188 15.19 Chapter 15 Decision...

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