Control ENG HW_Part_23

# Control ENG HW_Part_23 - 3 according to step function. At...

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dt dh A q q = - 3 2 R h q 1 1 = R h q 2 2 = R h q = 3 So we get 0 1 = - S S q q 0 2 1 = - S S q q 0 3 2 = - S S q q writing in terms of deviation variables and taking laplace transforms ) ( ) ( ) ( 1 1 s H A R s H s Q S = - ) ( ) ( ) ( 2 2 1 s H A R s H R s Q S = - ) ( ) ( ) ( 2 s H A R s H R s H S = - solving we get 3 3 ) 1 ( 1 ) 1 ( ) ( ) ( + = + = s s R s Q s H τ 3 3 ) 1 ( 2 ) 1 ( ) ( ) ( + = + = s s s Q s H

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{ } t e t s H L t H - - = = 2 2 ) ( ) ( 2 1 t e t t H - = 2 ) ( 0 2 ) ( = - = - - t t te te dt t dH 2 2 t t = = at t = 2 max will occur. 7.6 In the two- tank mixing process shown in fig P7.6 , x varies from 0 lb salt/ft 3 to 1 lb salt/ft
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Unformatted text preview: 3 according to step function. At what time does the salt concentration in tank 2 reach 0.6 lb/ ft 3 ? The hold up volume of each tank is 6 ft 3 . Solution Writing heat balance equation for tank 1 and tank 2 dt dy V q q y x =-...
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## This note was uploaded on 11/13/2011 for the course COP 4355 taught by Professor Koslov during the Spring '10 term at University of Florida.

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Control ENG HW_Part_23 - 3 according to step function. At...

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