Using
fig8.5, for
2
.
1
=
ξ
,
we
see
that
maximum
is
attained
at
min
776
.
1
,
95
.
0
=
=
t
t
τ
And
the
maximum
value
is
around
325
.
0
2
=
τ
Y
2
(t)
=
0.174
=
H
2
(t)
=
0.174x3.5
=
0.16ft
thus
max
deviation
is
H
1
will
be
at
t
=
0
=
H
1
=
1
ft
max
deviation
is
H
2
will
be
at
t
=
1.776
min =
H
2Max
=
0.61 ft.
comment
:
the
first
tank
gets
the
impulse
and
hence
it
max
deviation
turns
out
to
be
higher
than
the
deviations
for
the
second
tank.
The
second
tank
exhibits
an
increase
response
ie
the
deviation
increases,
reaches
the
H
2Max
falls
off to
zero.
8.3
The
tank
liquid
level
shown
operates
at
steady
state
when
a
step
change
is
made
in
the
flow
to
tank
1.the
transaient
response
in
critically
damped,
and
it
takes
1
min
for
level
in
second
tank
to
reach 50 %
of
total
change.
If A
1
/A
2
=
2
,find
R
1
/R
2
.
calculate
τ
for
each
tank.
How
long
does
it
take
for
level
in
first
tank
to
reach
90%
of
total
change?
For
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 Spring '10
 Koslov
 Steady State, Tank, Reach, All wheel drive vehicles, H1

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