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Control ENG HW_Part_38

# Control ENG HW_Part_38 - from tank 2 H 2 s R2 1.5 = = Q s 1...

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from tank 2, ) 1 3 )( 1 ( 5 . 1 ) 1 )( 1 ( ) ( ) ( 2 1 2 2 + + = + + = s s s s R s Q s H τ τ for tank 3, dt dh A q q c 3 3 2 = - dt dh A Q const q q c 3 3 2 3 ) ( = = = dt dh A R H 3 3 2 2 = thus, s s H s H R s H s SH A 3 1 ) ( ) ( ) ( ) ( 2 3 2 2 3 3 = = = s s H s H R s H s SH A 3 1 ) ( ) ( ) ( ) ( 2 3 2 2 3 3 = = = ) 1 3 )( 1 ( 5 . 0 ) ( ) ( 3 + + = s s s s Q s H 8.11© ) 1 ( 5 ) ( 1 + = s s H t e t H - = 5 ) ( 1 A H 155 . 0 ) 46 . 3 ( 1 = 1 4 3 5 . 1 ) ( ) ( 2 2 + + = s s s Q s H 1 4 3 5 . 7 ) ( 5 ) 1 ( 2 2 + + = = = s s s H Q

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3 = τ 4 2 = ξτ 155 . 1 3 2 4 2 4 = = = τ ξ from fig 8.5 τ ξ t and 155 . 1 = = 2 3 46 . 3 = = = τ ξ t 5 . 7 265 . 0 ) ( 2 X t H = τ 147 . 1 5 . 7 265 . 0 ) ( 2 = = τ X t H ) 1 4 3 ( 5 . 0 ) ( ) ( 2 3 + + = s s s s Q s H ) 1 4 3 ( 5 . 2 ) ( 5 ) ( 2 3 + + = = = s s s s H s Q 3
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Control ENG HW_Part_38 - from tank 2 H 2 s R2 1.5 = = Q s 1...

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