This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: (a) Obtain an expression for the laplace transform of the temperature of inner tank T(s). (b) Invert T(s) and obtain T for t= 0,5,10, ∞ Solution: (a) For outer tank WC(Ti – T o ) + hA (T 1 – T 2 ) WC(T 2 – T o ) = ρ C V 2 dt dT 2 (1) At steady state WC(Tis – T o ) + hA (T 1s – T 2s ) WC(T 2s – T o ) = 0  (2) (1) – (2) gives WCTi’ + hA (T 1 ’ – T 2 ’) WCT 2 ’ = ρ C V 2 dt dT ' 2 Substituting numerical values 10 Ti’ + 10 ( T 1 ’ – T 2 ’) – 10 T 2 ’ = 50 dt dT ' 2 Taking L.T. Ti(s) + T 1 (s) – 2T 2 (s) = 5 s T 2 (s) Now Ti(s) = 0, since there is no change in temp of feed stream to outer tank. Which gives s s T s T 5 2 1 ) ( ) ( 1 2 + = Q 10 lb/hr T 1 T 2...
View
Full
Document
This note was uploaded on 11/13/2011 for the course COP 4355 taught by Professor Koslov during the Spring '10 term at University of Florida.
 Spring '10
 Koslov

Click to edit the document details