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Unformatted text preview: natively, for the sake of variety, one could apply the conclusion. Thus, from < a < b it follows (by Sigmon 1.15(j)) that 1 b < 1 a whence 1 b < 1 b + 1 a 2 < 1 a and therefore a < 2 1 a + 1 b < b ( Sigmon 1.15(j) again). 1...
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This note was uploaded on 11/12/2011 for the course MAS 3300 taught by Professor Staff during the Fall '08 term at University of Florida.
- Fall '08