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Unformatted text preview: + . As (rearranging) z- < , there exists a A such that z- < a (recall that = lub A ). As (rearranging) z-a < , there exists b B such that z-a < b (recall that = lub B ). The resulting inequality z < a + b shows that z is not an upper bound of S . (iii) Though nonempty, P need not be bounded above: indeed, A and B may contain arbitrarily large negative numbers. 1...
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This note was uploaded on 11/12/2011 for the course MAS 3300 taught by Professor Staff during the Fall '08 term at University of Florida.
- Fall '08