Solutions to Problem Set 2

Solutions to Problem Set 2 - Solution of Problem Set 2...

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Solution of Problem Set 2 Problem 1 a&b. Calc>>random data>>normal Number of rows of data to generate: 100 Store in column: C1 Mean: 0 Standard Deviation: 1 Then go to Stat>>Basic Statistics>> Graphical Summary 3 2 1 0 -1 -2 -3 Median Mean 0.05 0.00 -0.05 -0.10 -0.15 1st Q uartile -0.77079 Median -0.05435 3rd Q uartile 0.64611 Maximum 3.04649 -0.09697 0.03091 -0.15353 0.05482 0.98717 1.07770 A-Squared 0.29 P-V alue 0.618 Mean -0.03303 StDev 1.03044 V ariance 1.06180 Skewness 0.076244 Kurtosis -0.118113 N 1000 Minimum -3.13480 Anderson-Darling Normality Test 95% Confidence Interval for Mean 95% Confidence Interval for Median 95% Confidence Interval for StDev 95% Confidence Intervals Summary for C1 c. YES d&e. First you have to identify which observation are in the interval xs ± . In my case, x =-0.03 and s =1.03. Everyone should have different numbers here. Go to Calc>>calculator, and then enter C1 >=-0.03 -1.03 And C1 <=-0.03+ 1.03 in the expression box. Save the result in variable C2. If C2=1, those observations are in the interval ± . You can use Calc>>column statistics>> mean to compute the
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percentage, or simply use pie chart. Repeat this procedure for 2 xs ± and 3 ± .
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This note was uploaded on 11/14/2011 for the course ECON UA.18.1-01 taught by Professor Romanfrydman during the Fall '11 term at NYU.

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Solutions to Problem Set 2 - Solution of Problem Set 2...

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