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Lecture6_hw_ksturdevant

Lecture6_hw_ksturdevant - 3 2 H 10-4 = OH HCO 3 2 CO 3 2 pH...

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Kimberly Sturdevant Lecture 6 Homework problems due 10-18-2011 10 -2 M NaHCO 3 Species : H + , H 2 O, OH - , HCO 3 , CO 3 2- ,H 2 CO 3 ,Na + Proton Condition: -2 -1 0 1 2 OH - H 2 O H + CO 3 2- HCO 3 H 2 CO 3 H 2 CO 3 10 -4.94 NaHCO 3 10 -2 TOTHin = TOTHeq TOTHin= 10-2 TOTHeq= { H + } -{ OH - }-{ HCO 3 - } -2 { CO 3 2- } { H + } + 10-2 ={ OH - }+{ HCO 3 - } +2 { CO 3 2- } pH = 9.2 10 -4 Na 2 CO 3 Species : H + , H 2 O, OH - , HCO 3 , CO 3 2- ,H 2 CO 3 ,Na + Proton Condition: -2 -1 0 1 2 OH - H 2 O H + CO 3 2- HCO 3 H 2 CO 3 H 2 CO 3 10 -4.94 NaHCO 3 10 -4
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TOTHin = TOTHeq TOTHin= 10 -4 TOTHeq= { H + } -{ OH - }-{ HCO
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Unformatted text preview: 3 2-} { H + } + 10-4 ={ OH-}+{ HCO 3-} +2 { CO 3 2-} pH = 7.6 10-4 NaOH Species : H + , H 2 O, OH-, HCO 3 , CO 3 2-,H 2 CO 3 ,Na + Proton Condition: -2-1 1 2 OH-H 2 O H + CO 3 2-HCO 3 H 2 CO 3 H 2 CO 3 10-4.94 NaOH 10-4 TOTHin = TOTHeq TOTHin= 10-4 TOTHeq= { H + } -{ OH-}-{ HCO 3-} -2 { CO 3 2-} { H + } + 10-4 ={ OH-}+{ HCO 3-} +2 { CO 3 2-} pH = 7.2...
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