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Unformatted text preview: 5. Let the volume of the expanded air sacs be Va and that of the ﬁsh with its air sacs collapsed be V . Then
ρﬁsh = mﬁsh
3
= 1.08 g/cm
V and ρw = mﬁsh
3
= 1.00 g/cm .
V + Va where ρw is the density of the water. This implies ρﬁsh V = ρw (V + Va ) or (V + Va )/V = 1.08/1.00,
which gives Va /(V + Va ) = 7.4%. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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