P15_018 - 18. (a) The force on face A of area AA is FA = pA...

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18. (a) The force on face A of area A A is F A = p A A A = ρ w gh A A A =2 ρ w gd 3 =2 ³ 1 . 0 × 10 3 kg / m 3 ´ ( 9 . 8m / s 2 ) (5 . 0m) 3 =2 . 5 × 10 6 N . (b) The force on face B is F B = p avg B A B = ρ w g µ 5 d 2 d 2 = 5 2 ρ w gd 3 = 5 2 ³ 1 . 0 × 10 3 kg / m 3 ´ ( 9 . 8m / s 2 ) (5 . 0m) 3 =3 . 1 × 10 6 N . Note that these Fgures are due to the water pressure only. If you add the contribution from the atmospheric pressure, then you need to add F
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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