Unformatted text preview: p 2 = p 1 − Z h ρg dy . Assuming ρ = ρ (1 − y/h ), where ρ is the density at Earth’s surface and g = 9 . 8 m / s 2 for 0 ≤ y ≤ h , the integral becomes p 2 = p 1 − Z h ρ g ³ 1 − y h ´ dy = p 1 − 1 2 ρ gh . Since p 2 = 0, this implies h = 2 p 1 ρ g = 2(1 . 01 × 10 5 Pa) (1 . 3 kg / m 3 )(9 . 8 m / s 2 ) = 16 × 10 3 m = 16 km ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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