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Unformatted text preview: p 2 = p 1 Z h g dy . Assuming = (1 y/h ), where is the density at Earths surface and g = 9 . 8 m / s 2 for 0 y h , the integral becomes p 2 = p 1 Z h g 1 y h dy = p 1 1 2 gh . Since p 2 = 0, this implies h = 2 p 1 g = 2(1 . 01 10 5 Pa) (1 . 3 kg / m 3 )(9 . 8 m / s 2 ) = 16 10 3 m = 16 km ....
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 Fall '08
 SPRUNGER
 Physics

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