P15_034

# P15_034 - m is m m = m m brass m = 1 1 air / 1 air / brass...

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34. Let F o be the buoyant force of air exerted on the object (of mass m and volume V ), and F brass be the buoyant force on the brass weights (of total mass m brass and volume V brass ). Then we have F o = ρ air Vg = ρ air µ mg ρ and F brass = ρ air V brass g = ρ air µ m brass ρ brass . For the two arms of the balance to be in mechanical equilibrium, we require mg F o = m brass g F brass , or mg mg µ ρ air ρ = m brass g m brass g µ ρ air ρ brass , which leads to m brass = µ 1 ρ air 1 ρ air brass m. Therefore, the percent error in the measurement of
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Unformatted text preview: m is m m = m m brass m = 1 1 air / 1 air / brass = air (1 / 1 / brass ) 1 air / brass = . 0012(1 / 1 / 8 . 0) 1 . 0012 / 8 . . 0012 1 1 8 . , where is in g / cm 3 . Stating this as a percent error, our result is 0 . 12% multiplied by 1 1 8 . ....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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