P15_036 - NV . The density of water is 1000 kg / m 3 . To...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
36. The problem intends for the children to be completely above water. The total downward pull of gravity on the system is 3(356 N) + wood gV where N is the (minimum) number of logs needed to keep them afloat and V i sthevo lumeo feach log: V = π (0 . 15 m) 2 (1 . 80 m) = 0 . 13 m 3 . The buoyant force is F b = ρ water gV submerged
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: NV . The density of water is 1000 kg / m 3 . To obtain the minimum value of N we set V submerged = NV and then round our answer for N up to the nearest integer: 3(356 N) + N wood gV = water gNV = N = 3(356 N) gV ( water wood ) which yields N = 4 . 28 5 logs....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online