P15_036

# P15_036 - NV . The density of water is 1000 kg / m 3 . To...

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36. The problem intends for the children to be completely above water. The total downward pull of gravity on the system is 3(356 N) + wood gV where N is the (minimum) number of logs needed to keep them aﬂoat and V i sthevo lumeo feach log: V = π (0 . 15 m) 2 (1 . 80 m) = 0 . 13 m 3 . The buoyant force is F b = ρ water gV submerged
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Unformatted text preview: NV . The density of water is 1000 kg / m 3 . To obtain the minimum value of N we set V submerged = NV and then round our answer for N up to the nearest integer: 3(356 N) + N wood gV = water gNV = N = 3(356 N) gV ( water wood ) which yields N = 4 . 28 5 logs....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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