P15_039 - 2 ( NA 2 ) = v 2 = A 1 NA 2 v 1 = R 2 Nr 2 v 1...

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39. We use the equation of continuity. Let v 1 bethespeedo fthewaterinthehoseand v 2 be its speed as it leaves one of the holes. A 1 = πR 2 is the cross-sectional area of the hose. If there are N holes and A 2 is the area of a single hole, then the equation of continuity becomes v 1 A 1 =
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Unformatted text preview: 2 ( NA 2 ) = v 2 = A 1 NA 2 v 1 = R 2 Nr 2 v 1 where R is the radius of the hose and r is the radius of a hole. Noting that R/r = D/d (the ratio of diameters) we Fnd v 2 = D 2 Nd 2 v 1 = (1 . 9 cm) 2 24(0 . 13 cm) 2 (0 . 91 m / s) = 8 . 1 m / s ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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