P15_055 - v = s 2(32 10 4 m 2 ) 2 (55 10 3 Pa 41 10 3 Pa)...

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55. (a) The continuity equation yields Av = aV , and Bernoulli’s equation yields ∆ p + 1 2 ρv 2 = 1 2 ρV 2 ,where p = p 1 p 2 . The frst equation gives V =( A/a ) v . We use this to substitute For V in the second equation, and obtain ∆ p + 1 2 ρv 2 = 1 2 ρ ( A/a ) 2 v 2 .W eso lv eFo r v . The result is v = v u u u t 2∆ p ρ µ A 2 a 2 1 = s 2 a 2 p ρ ( A 2 a
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Unformatted text preview: v = s 2(32 10 4 m 2 ) 2 (55 10 3 Pa 41 10 3 Pa) (1000 kg / m 3 ) ( (64 10 4 m 2 ) 2 (32 10 4 m 2 ) 2 ) = 3 . 06 m / s . Consequently, the ow rate is Av = ( 64 10 4 m 2 ) (3 . 06 m / s) = 2 . 10 2 m 3 / s ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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