P15_074 - 02 × 10 − 3 m 3 is the volume of the object...

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74. Neglecting the buoyant force caused by air, then the 30 N value is interpreted as the true weight W of the object. The buoyant force of the water on the object is therefore 30 20 = 10 N, which means F b = ρ w Vg = V = 10N (1000 kg / m 3 )(9 . 8m / s 2 ) =1
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Unformatted text preview: . 02 × 10 − 3 m 3 is the volume of the object. When the object is in the second liquid, the buoyant force is 30 − 24 = 6 N, which implies ρ 2 = 6 N (9 . 8 m / s 2 ) (1 . 02 × 10 − 3 m 3 ) = 600 kg / m 3 ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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