This preview shows page 1. Sign up to view the full content.
Unformatted text preview: . 47)(3 . 2)(24)(71) / 48 2 = 2 . 2. (b) To compute the torque due to the water pressure, we will need to integrate Eq. 157 (multiplied by ( d − y ) and the dam width w ) as shown below. The countertorque due to the weight of the concrete is the weight multiplied by half the thickness ` , since we take the center of mass of the dam is at its geometric center and the axis of rotation at A . Thus, the safety factor relative to rotation is mg ` 2 R d o ρ w gy ( d − y ) w dy = ρ c `whg ` 2 1 6 ρ w gwd 3 = 3 ρ c ` 2 h ρ w d 3 which yields 3(3 . 2)(24) 2 (71) / (48) 3 = 3 . 55....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Force

Click to edit the document details