P15_084 - must equal the upward buoyant force exerted by...

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84. The area facing down (and up) is A =(0 . 050 m)(0 . 040 m) = 0 . 0020 m 2 . The submerged volume is V = Ad where d =0 . 015 m. In order to float, the downward pull of gravity mg
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Unformatted text preview: must equal the upward buoyant force exerted by the seawater of density ρ : mg = ρV g = ⇒ m = ρV = (1025)(0 . 0020)(0 . 015) = 0 . 031 kg ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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