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86. Note that “surface area” refers to the
total
surface area of all six faces, so that the area of each (square)
face is 24
/
6=4m
2
. From Archimedes’ principle and the requirement that the cube (of total volume
V
and density
ρ
) ﬂoats, we ±nd
ρV g
=
ρ
w
V
sub
g
=
⇒
ρ
ρ
w
=
V
sub
V
for the fraction of volume submerged. The assumption that the cube ﬂoats upright, as described in this
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Unformatted text preview: problem, simpli±es this relation to ρ ρ w = h sub h where h is the length of one side, and ρ w = 4 ρ is given. With h = √ 4 = 2 m, we ±nd h sub = h/ 4 = 0 . 50 m....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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