P15_086 - problem, simpli±es this relation to ρ ρ w = h...

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86. Note that “surface area” refers to the total surface area of all six faces, so that the area of each (square) face is 24 / 6=4m 2 . From Archimedes’ principle and the requirement that the cube (of total volume V and density ρ ) floats, we ±nd ρV g = ρ w V sub g = ρ ρ w = V sub V for the fraction of volume submerged. The assumption that the cube floats upright, as described in this
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Unformatted text preview: problem, simpli±es this relation to ρ ρ w = h sub h where h is the length of one side, and ρ w = 4 ρ is given. With h = √ 4 = 2 m, we ±nd h sub = h/ 4 = 0 . 50 m....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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