This preview shows page 1. Sign up to view the full content.
Unformatted text preview: A 2 = A 1 / 2 treated in the Sample Problem. Note that ∆ p = p 1 − p 2 = − 7 . 2 × 10 3 Pa and A 2 1 − A 2 2 = − 8 . 66 × 10 − 3 m 4 , so that the square root is well deFned. Therefore, we obtain R = 0 . 0776 m 3 /s. (b) The mass rate of ﬂow is ρR = 68 . 9 kg/s....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details