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Unformatted text preview: 9. Using v = f λ, we ﬁnd the length of one cycle of the wave is λ = 350/500 = 0.700 m = 700 mm. From
f = 1/T , we ﬁnd the time for one cycle of oscillation is T = 1/500 = 2.00 × 10−3 s = 2.00 ms.
(a) A cycle is equivalent to 2π radians, so that π/3 rad corresponds to onesixth of a cycle. The
corresponding length, therefore, is λ/6 = 700/6 = 117 mm.
(b) The interval 1.00 ms is half of T and thus corresponds to half of one cycle, or half of 2π rad. Thus,
the phase diﬀerence is (1/2)2π = π rad. ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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