P17_030 - 30. The phasor diagram is shown below. We use the...

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Unformatted text preview: 30. The phasor diagram is shown below. We use the cosine theorem: 2 2 2 2 2 ym = ym1 + ym2 − 2ym1 ym2 cos θ = ym1 + ym2 + 2ym1 ym2 cos φ . . .. ... .. ....... ....... ... ... .. . . .. . .. . . . . .. . .. . .. .. . .. . .. . . .. . .. . . . m ...... . . . . . . . . .. . .. . . .. . .. . . .. . .. . . .. . .. . . . . .. . . .. . .. . . .. . .. . . .. . .. . . . . .. . .. . .. . . . .. .. . . . .. .. . . . . . . . .. .. . .. .. ................................ . ............................ . . .. . ... .. . y • ym2 θφ ym1 We solve for cos φ: cos φ = = = 2 2 2 ym − ym1 − ym2 2ym1 ym2 (9.0 mm)2 − (5.0 mm)2 − (7.0 mm)2 2(5.0 mm)(7.0 mm) 0.10 . The phase constant is therefore φ = 84◦ . ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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