P17_044 - mass-per-unit-length is µ = m/L =(0 044 kg(0 90 m = 0 049 kg/m Thus using Eq 17-25 we obtain the tension τ = v 2 µ =(27 2(0 049 = 36 N.

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44. To oscillate in four loops means n = 4 in Eq. 17-52 (treating both ends of the string as eFectively “±xed’). Thus, λ =2(0 . 90 m) / 4=0 . 45 m . Therefore, the speed of the wave is v = =27m/s
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Unformatted text preview: mass-per-unit-length is µ = m/L = (0 . 044 kg) / (0 . 90 m) = 0 . 049 kg/m. Thus, using Eq. 17-25, we obtain the tension: τ = v 2 µ = (27) 2 (0 . 049) = 36 N....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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