P17_045 - is the angular frequency. The angular wave number...

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45. (a) Since the string has four loops its length must be two wavelengths. That is, λ = L/ 2, where λ is the wavelength and L is the length of the string. The wavelength is related to the frequency f and wave speed v by λ = v/f ,so L/ 2= v/f and L =2 v/f = 2(400 m / s) / (600 Hz) = 1 . 3m. (b) We write the expression for the string displacement in the form y = y m sin( kx )cos( ωt ), where y m is the maximum displacement, k is the angular wave number, and
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Unformatted text preview: is the angular frequency. The angular wave number is k = 2 / = 2 f/v = 2 (600 Hz) / (400 m / s) = 9 . 4 m 1 and the angular frequency is = 2 f = 2 (600 Hz) = 3800 rad / s. y m is 2 . 0 mm. The displacement is given by y ( x, t ) = (2 . 0 mm) sin[(9 . 4 m 1 ) x ] cos (3800 s 1 ) t ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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