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Unformatted text preview: equality of the frequencies for the two sections now leads to n 1 /L 1 1 = n 2 /L 2 2 , where A has been canceled from both sides. The ratio of the integers is n 2 n 1 = L 2 2 L 1 1 = (0 . 866 m) q 7 . 80 10 3 kg / m 3 (0 . 600 m) q 2 . 60 10 3 kg / m 3 = 2 . 5 . The smallest integers that have this ratio are n 1 = 2 and n 2 = 5. The frequency is f = n 1 v 1 / 2 L 1 = ( n 1 / 2 L 1 ) p / 1 A . The tension is provided by the hanging block and is = mg , where m is the mass of the block. Thus f = n 1 2 L 1 r mg 1 A = 2 2(0 . 600 m) s (10 . 0 kg)(9 . 8 m / s 2 ) (2 . 60 10 3 kg / m 3 )(1 . 00 10 6 m 2 ) = 324 Hz . (b) The standing wave pattern has two loops in the aluminum section and ve loops in the steel section, or seven loops in all. There are eight nodes, counting the end points....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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