P17_052 - 2(300) which gives d = 6 . 10 3 m. This and the...

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52. (a) This distance is determined by the longitudinal speed: d ` = v ` t = (2000 m / s) ( 40 × 10 6 s ) =8 . 0 × 10 2 m . (b) Assuming the acceleration is constant (justifed by the near-straightness oF the curve a = 300 / 40 × 10 6 ) we fnd the stopping distance d : v 2 = v 2 o +2 ad = d = (300) 2 ( 40 × 10 6 )
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Unformatted text preview: 2(300) which gives d = 6 . 10 3 m. This and the radius r Form the legs oF a right triangle (where r is opposite From = 60 ). ThereFore, tan 60 = r d = r = d tan 60 = 1 . 10 2 m ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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