P17_056 - p ( 1 . 66) 2 + 4 . 11 2 = 4 . 4 mm . (b) And the...

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56. We orient one phasor along the x axis with length 4 . 0 mm and angle 0 and the other at 0 . 8 π rad = 144 (in the second quadrant) with length 7 . 0 mm. Adding the components, we obtain 4 . 0+7 . 0 cos(144 )= 1 . 66 mm along x axis 7 . 0 sin(144 )=4 . 11 mm along y axis . (a) The amplitude of the resultant wave is consequently
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Unformatted text preview: p ( 1 . 66) 2 + 4 . 11 2 = 4 . 4 mm . (b) And the phase constant (an angle, measured counterclockwise from the + x axis) is 180 + tan 1 4 . 11 1 . 66 = 112 ....
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