P17_059 - 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 2 4 6 8 10 12...

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59. (a) Recalling the discussion in § 17-5, we see that the speed of the wave given by a function with argument x 5 t (where x is in centimeters and t is in seconds) must be 5 cm/s. (b) In part (c), we show several “snapshots” of the wave: the one on the left is as shown in Figure 17-47 (at t = 0), the middle one is at t =1 . 0 s, and the rightmost one is at t =2 . 0s . Itisc lear that the wave is traveling to the right (the + x direction).
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Unformatted text preview: 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 2 4 6 8 10 12 14 (d) The leading edge of the pulse reaches x = 10 cm at t = (10 4) / 5 = 1 . 2 s. The particle (say, of the string that carries the pulse) at that location reaches a maximum displacement h = 2 cm at t = (10 3) / 5 = 1 . 4 s. Finally, the the trailing edge of the pulse departs from x = 10 cm at t = (10 1) / 5 = 1 . 8 s. Thus, we nd for h ( t ) at x = 10 cm (with the horizontal axis, t , in seconds): 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 1.2 1.3 1.4 1.5 1.6 1.7 1.8...
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