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70.
(a) Recalling from Ch
.
12 the simple harmonic motion relation
u
m
=
y
m
ω
,wehave
ω
=
16
0
.
04
= 400 rad
/
s
.
Since
ω
=2
πf
,weobta
in
f
=64Hz
.
(b) Using
v
=
fλ
, we Fnd
λ
=80
/
64 = 1
.
26 m.
(c) Now,
k
=2
π/λ
= 5 rad/m, so the function describing the wave becomes
y
=0
.
04 sin(5
x
−
400
t
+
φ
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 Fall '08
 SPRUNGER
 Physics, Simple Harmonic Motion

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