P18_002 - (3 × 10 5 km s = 0 02 s So the listener 5000 km...

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2. We denote the speed of light c =3 . 0 × 10 8 m/s. The time t 1 it takes for you to hear the music is t 1 = D 1 /v s = (300 m) / (343 m / s) = 0 . 87s . The time t 2 it takes for a listener 5000 km away to hear the music is t 2 = D 2 /c = 5000 km /
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Unformatted text preview: (3 × 10 5 km / s) = 0 . 02 s . So the listener 5000 km away actually hears the music Frst! The time di±erence is ∆ t = t 1 − t 2 = 0 . 87 s − . 02 s = 0 . 85 s ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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