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Unformatted text preview: d 1 = v t 1 = (343 m / s)(0 . 23 s) = 79 m. The distance from the kicker to the second spectator is d 2 = v t 2 = (343 m / s)(0 . 12 s) = 41 m. (b) Lines from the kicker to each spectator and from one spectator to the other form a right triangle with the line joining the spectators as the hypotenuse, so the distance between the spectators is D = p d 2 1 + d 2 2 = p (79 m) 2 + (41 m) 2 = 89 m....
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 Fall '08
 SPRUNGER
 Physics, Light

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