This preview shows page 1. Sign up to view the full content.
Unformatted text preview: t/v s ) d + (1 /v 2 s ) d 2 . Now multiply by gv 2 s and rearrange to get gd 2 2 v s ( gt + v s ) d + gv 2 s t 2 = 0. This is a quadratic equation for d . Its solutions are d = 2 v s ( gt + v s ) p 4 v 2 s ( gt + v s ) 2 4 g 2 v 2 s t 2 2 g . The physical solution must yield d = 0 for t = 0, so we take the solution with the negative sign in front of the square root. Once values are substituted the result d = 40 . 7 m is obtained....
View Full
Document
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details