Unformatted text preview: âˆ† Ï† â‰ˆ 2 Ï€ âˆ† x Î» = 2 Ï€D sin Î¸ Î» = 4 Ï€ sin Î¸ . (a) Â²or maximum signal, we set âˆ† Ï† = 2 mÏ€ ( m = 0 , Â± 1 , Â± 2 ,... ) to obtain sin Î¸ = m/ 2. Thus we get a total of 8 possible values of Î¸ between 0 and 2 Ï€ , given by Î¸ = 0 , sin âˆ’ 1 (1 / 2) = 30 â—¦ , sin âˆ’ 1 (1) = 90 â—¦ and (using symmetry properties of the sine function) 150 â—¦ , 180 â—¦ , 210 â—¦ , 270 â—¦ , and 330 â—¦ . (b) Since there must be a mininum in between two successive maxima, the total number of minima is also eight....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Work

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