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Unformatted text preview: 16. At the location of the detector, the phase diﬀerence between the wave which traveled straight down the
tube and the other one which took the semi-circular detour is
∆φ = k ∆d = 2π
(πr − 2r) .
λ For r = rmin we have ∆φ = π , which is the smallest phase diﬀerence for a destructive interference to
= 17.5 cm .
2(π − 2)
2(π − 2) ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08