P18_016 - 16. At the location of the detector, the phase...

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Unformatted text preview: 16. At the location of the detector, the phase difference between the wave which traveled straight down the tube and the other one which took the semi-circular detour is ∆φ = k ∆d = 2π (πr − 2r) . λ For r = rmin we have ∆φ = π , which is the smallest phase difference for a destructive interference to occur. Thus λ 40.0 cm rmin = = = 17.5 cm . 2(π − 2) 2(π − 2) ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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