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Unformatted text preview: displacement amplitude is the sum of the amplitudes of the individual waves: s m = s SAD + s SBD . Solve 100 = C ( s SAD s SBD ) and 900 = C ( s SAD + s SBD ) for s SAD and s SBD . Add the equations to obtain s SAD = ( 100 + 900) / 2 C = 20 /C , then subtract them to obtain s SBD = ( 900 100) / 2 C = 10 /C . The ratio of the amplitudes is s SAD /s SBD = 2. (c) Any energy losses, such as might be caused by frictional forces of the walls on the air in the tubes, result in a decrease in the displacement amplitude. Those losses are greater on path B since it is longer than path A....
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- Fall '08