P18_034

# P18_034 - A / C = 528 Hz / 440 Hz = 1 . 2. (c) This has the...

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34. (a) The fundamental frequency of a string can be increased (for instance, going from A up to C) by shortening the length of the vibrating portion of the string. When the note C is played, the vibrating length is (using Eq. 17-53) f 0 f = nv/ 2 L 0 nv/ 2 L = L =(30cm) µ 440 Hz 528 Hz =25cm . Thus, one should place his Fnger a distance of 30 cm 25 cm = 5 cm from one end of the string. (b) Since v = , the ratio of wavelengths is the reciprocal of the frequency ratio, so that
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Unformatted text preview: A / C = 528 Hz / 440 Hz = 1 . 2. (c) This has the same answer as part (b), due to the fact that the frequencies are the same on the string and the air (transmitting a signal from one medium to another does not generally change its frequency. Both wavelengths are larger ( much larger) in the air than on the string, but their ratio (due to v = f ) remains the same....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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