P18_036

# P18_036 - / = f/f = 1 / 1 . 2 = 5 / 6. This ratio applies...

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36. (a) Using Eq. 17-53 with n = 1 (for the fundamental mode of vibration), we obtain f 0 f = (1) v/ 2 L 0 (1) v/ 2 L = L L 0 so that f 0 = rf (where r is a pure number) implies L 0 = L/r . Thus, the amount if must be shortened is l =∆ L = L L 0 = L (1 1 /r ). (b) With L =80cmand r =1 . 2, this yields l =13cm. (c) Since v = , the ratio of wavelengths is the reciprocal of the ratio of frequencies: λ
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Unformatted text preview: / = f/f = 1 / 1 . 2 = 5 / 6. This ratio applies to the wavelength ratio for the vibrating string and also for the wavelength ratio for the emitted sound waves (due to the fact that the frequency of a signal is generally not altered when transmitted from one medium to another)....
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## This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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