Unformatted text preview: 41. The string is ﬁxed at both ends so the resonant wavelengths are given by λ = 2L/n, where L is the length
of the string and n is an integer. The resonant frequencies are given by f = v/λ = nv/2L, where v is the
wave speed on the string. Now v = τ /µ, where τ is the tension in the string and µ is the linear mass
density of the string. Thus f = (n/2L) τ /µ. Suppose the lower frequency is associated with n = n1
and the higher frequency is associated with n = n1 + 1. There are no resonant frequencies between so
you know that the integers associated with the given frequencies diﬀer by 1. Thus f1 = (n1 /2L) τ /µ
and
n1 + 1 τ
1
n1
1
τ
τ
τ
f2 =
=
+
= f1 +
.
2L
µ
2L µ 2L µ
2L µ
This means f2 − f1 = (1/2L) τ /µ and
τ =
=
= 4L2 µ(f2 − f1 )2
4(0.300 m)2 (0.650 × 10−3 kg/m)(1320 Hz − 880 Hz)2
45.3 N . ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

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