P18_062 - 62. (a) Using Eq. 18-39 with v = 343 m/s and n =...

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Unformatted text preview: 62. (a) Using Eq. 18-39 with v = 343 m/s and n = 1, we find f = nv/2L = 86 Hz for the fundamental frequency in a nasal passage of length L = 2.0 m (subject to various assumptions about the nature of the passage as a “bent tube open at both ends”). (b) The sound would be perceptible as sound (as opposed to just a general vibration) of very low frequency. (c) Smaller L implies larger f by the formula cited above. Thus, the female’s sound is of higher pitch (frequency). ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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