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Unformatted text preview: = ( R − 1) v ( R + 1) cos θ = 0 . 90 m / s where v = 1540 m/s, θ = 20 ◦ , and R = 1 + 5495 / 5 × 10 6 . (c) We interpret the question as asking how ∆ f (still taken to be positive, since the detector is in the “forward” direction) changes as the detection angle θ changes. Since larger θ means smaller horizontal component of velocity v x then we expect ∆ f to decrease towards zero as θ is increased towards 90 ◦ ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
- Fall '08