P18_096 - 440 = 1 0091 With v S designating the speed of...

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96. Since they are approaching each other, the sound produced (of emitted frequency f ) by the flatcar- trumpet received by an observer on the ground will be of higher pitch f 0 . In these terms, we are told f 0 f =4 . 0 Hz, and consequently that f 0 /f = 444
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Unformatted text preview: / 440 = 1 . 0091. With v S designating the speed of the flatcar and v = 343 m/s being the speed of sound, the Doppler equation leads to f f = v + 0 v − v S = ⇒ v S = (343) 1 . 0091 − 1 1 . 0091 = 3 . 1 m / s ....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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