P18_097 - 97. The siren is between you and the cliff,...

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Unformatted text preview: 97. The siren is between you and the cliff, moving away from you and towards the cliff. Both “detectors” (you and the cliff) are stationary, so vD = 0 in Eq. 18-47 (and see the discussion in the textbook immediately after that equation regarding the selection of ± signs). The source is the siren with vS = 10 m/s. The problem asks us to use v = 330 m/s for the speed of sound. (a) With f = 1000 Hz, the frequency fy you hear becomes fy = f v+0 v + vS = 970.6 ≈ 9.7 × 102 Hz . (b) The frequency heard by an observer at the cliff (and thus the frequency of the sound reflected by the cliff, ultimately reaching your ears at some distance from the cliff) is fc = f v+0 v − vS = 1031.3 ≈ 1.03 × 102 Hz . (c) The beat frequency is fc − fy = 61 beats/s (which, due to specific features of the human ear, is too large to be perceptible). ...
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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