P18_099 - f = 950 Hz, we obtain f = 880 Hz. (b) We now have...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
99. (a) The problem asks for the source frequency f . We use Eq. 18-47 with great care (regarding its ± sign conventions). f 0 = f µ 340 16 340 40 Therefore, with
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: f = 950 Hz, we obtain f = 880 Hz. (b) We now have f = f 340 + 16 340 + 40 so that with f = 880 Hz, we Fnd f = 824 Hz....
View Full Document

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online