Unformatted text preview: entropy is ∆ S = Q/T , where Q is the energy it receives as heat (the negative of the energy it supplies the ice) and T is its temperature. When the ice warms to 0 ◦ C, Q = − mc I ( T f − T i ) = − (0 . 010 kg)(2220 J / kg · K)(10 K) = − 222 J . When the ice melts, Q = − mL F = − (0 . 010 kg)(333 × 10 3 J / kg) = − 3 . 33 × 10 3 J . When the water from the ice warms, Q = − mc w ( T f − T i ) = − (0 . 010 kg)(4190 J / kg · K)(15 K) = − 629 J . The total energy leaving the lake water is Q = − 222 J − 3 . 33 × 10 3 J − 6 . 29 × 10 2 J = − 4 . 18 × 10 3 J. The change in entropy is ∆ S = − 4 . 18 × 10 3 J 288 K = − 14 . 51 J / K . The change in the entropy of the icelake system is ∆ S = (15 . 27 − 14 . 51) J / K = 0 . 76 J / K....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics, Energy, Mass, Heat

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