16. In coming to equilibrium, the heat lost by the 100 cm3of liquid water (of massmw= 100 g and speciFcheat capacitycw= 4190 J/kg·K) is absorbed by the ice (of massmiwhich melts and reachesTf>0◦C).We begin by Fnding the equilibrium temperature:XQ=0Qwarm water cools+Qice warms to 0◦+Qice melts+Qmelted ice warmscwmw(Tf−20◦)+cimi(0◦−(−10◦)) +LFmi+cwmi(Tf−0◦)=0which yields, after usingLF= 333000 J/kg and values cited in the problem,Tf=12.24◦which isequivalent toTf= 285.39 K. Sample Problem 20-2 shows that∆Stemp change
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.