P21_026 - 26. (a) Eq. 21-11 leads to =1 TL 333 K =1 = 0.107...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
26. (a) Eq. 21-11 leads to ε =1 T L T H =1 333 K 373 K =0 . 107 . We recall that a Watt is Joule-per-second. Thus, the (net) work done by the cycle per unit time is the given value 500 J/s. Therefore, by Eq. 21-9, we obtain the heat input per unit time:
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

Ask a homework question - tutors are online