This preview shows page 1. Sign up to view the full content.
Unformatted text preview: WT L / ( T H T L ) = mc ( T f T i ) + mL F . We dierentiate with respect to time and replace dW/dt with P , the power output of the engine, and obtain PT L / ( T H T L ) = ( dm/dt )[ c ( T f T i ) + L F ]. Thus, dm dt = PT L T H T L 1 c ( T f T i ) + L F . Now, P = 100 10 6 W, T L = 0 + 273 = 273 K, T H = 800 + 273 = 1073 K, T i = 40 + 273 = 233 K, T f = 0 + 273 = 273 K, c = 2220 J / kg K, and L F = 333 10 3 J / kg, so dm dt = (100 10 6 J / s)(273 K) 1073 K 273 K 1 (2220 J / kg K)(273 K 233 K) + 333 10 3 J / kg = 82 kg / s . We note that the engine is now operated between 0 C and 800 C....
View
Full
Document
This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.
 Fall '08
 SPRUNGER
 Physics

Click to edit the document details