P21_039 - | t ´ K = 4000 Btu h(0 27(23 = 643 Btu h...

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39. We are told K =0 . 27 K C where K C = T L T H T L = 294 K 307 K 294 K =23 where the Fahrenheit temperatures have been converted to Kelvins. Expressed on a per unit time basis, Eq. 21-12 leads to | W | t = ³ | Q L
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Unformatted text preview: | t ´ K = 4000 Btu / h (0 . 27)(23) = 643 Btu / h . Appendix D indicates 1 But / h = 0 . 0003929 hp, so our result may be expressed as | W | /t = 0 . 25 hp....
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This note was uploaded on 11/12/2011 for the course PHYS 2001 taught by Professor Sprunger during the Fall '08 term at LSU.

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